/* Determine alignment of types. Copyright (C) 2003-2004, 2006, 2009-2019 Free Software Foundation, Inc. This program is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 3, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program; if not, see . */ #ifndef _ALIGNOF_H #define _ALIGNOF_H #include /* alignof_slot (TYPE) Determine the alignment of a structure slot (field) of a given type, at compile time. Note that the result depends on the ABI. This is the same as alignof (TYPE) and _Alignof (TYPE), defined in if __alignof_is_defined is 1. Note: The result cannot be used as a value for an 'enum' constant, due to bugs in HP-UX 10.20 cc and AIX 3.2.5 xlc. */ #if defined __cplusplus template struct alignof_helper { char __slot1; type __slot2; }; # define alignof_slot(type) offsetof (alignof_helper, __slot2) #else # define alignof_slot(type) offsetof (struct { char __slot1; type __slot2; }, __slot2) #endif /* alignof_type (TYPE) Determine the good alignment of an object of the given type at compile time. Note that this is not necessarily the same as alignof_slot(type). For example, with GNU C on x86 platforms: alignof_type(double) = 8, but - when -malign-double is not specified: alignof_slot(double) = 4, - when -malign-double is specified: alignof_slot(double) = 8. Note: The result cannot be used as a value for an 'enum' constant, due to bugs in HP-UX 10.20 cc and AIX 3.2.5 xlc. */ #if defined __GNUC__ || defined __IBM__ALIGNOF__ # define alignof_type __alignof__ #else # define alignof_type alignof_slot #endif #endif /* _ALIGNOF_H */